全部评论 2

  • #include<bits/stdc++.h>
    using namespace std;
    int main(){
    int n;
    cin >> n;
    long long a[70] = {};
    a[1] = 1, a[2] = 2;
    for(int i = 3; i <= n; i++) {
    a[i] = a[i - 1] + a[i - 2];
    }
    cout << a[n];
    return 0;
    }

    2025-08-20 来自 广东

    0
  • #include<bits/stdc++.h>
    using namespace std;正经题解
    int main(){
    int n;
    cin >> n;
    long long a[70] = {};
    a[1] = 1, a[2] = 2;
    for(int i = 3; i <= n; i++) {
    a[i] = a[i - 1] + a[i - 2];
    }
    cout << a[n];
    return 0;
    }

    2025-08-20 来自 广东

    0
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