题解
2023-03-04 17:44:05
发布于:上海
#include <stdio.h>
#include <string.h>
#include <iostream>
#include <algorithm>
#include <queue>
using namespace std;
const int N = 1010;
int n, m, p;
int s[N][N], cost[N];
int f[N], g[N][N];
struct Node
{
int v, i, j;
bool operator < (const Node & W) const
{
return v < W.v;
}
};
priority_queue<Node> heap[N];
int get(int x)
{
x %= n;
if (x <= 0)
{
x += n;
}
return x;
}
int main(void)
{
scanf("%d%d%d", &n, &m, &p);
for (int i = 1; i <= n; i++)
{
for (int j = 1; j <= m; j++)
{
scanf("%d", &s[i][j]);
}
}
for (int i = 1; i <= m; i++)
{
for (int j = 1; j <= n; j++)
{
if (j == 1)
{
s[j][i] += s[n][i - 1];
}
else
{
s[j][i] += s[j - 1][i - 1];
}
}
}
memset(f, -0x3f, sizeof f);
memset(g, -0x3f, sizeof g);
f[0] = 0;
for (int i = 1; i <= n; i++)
{
scanf("%d", &cost[i]);
}
for (int i = 1; i <= n; i++)
{
g[0][i] = -cost[get(i + 1)];
heap[get(0 - i)].push({ g[0][i], 0, i });
}
for (int i = 1; i <= m; i++)
{
for (int j = 1; j <= n; j++)
{
auto& h = heap[get(i - j)];
while (h.size())
{
auto t = h.top();
if (i - p > t.i)
{
h.pop();
}
else
{
f[i] = max(f[i], s[j][i] + t.v);
break;
}
}
}
for (int j = 1; j <= n; j++)
{
g[i][j] = f[i] - s[j][i] - cost[get(j + 1)];
heap[get(i - j)].push({ g[i][j], i, j });
}
}
int res = 0;
for (int i = 0; i <= m; i++)
{
res = max(res, f[i]);
}
cout << res << endl;
return 0;
}
全部评论 4
#include <stdio.h>
#include <string.h>
#include <iostream>
#include <algorithm>
#include <queue>
using namespace std;
const int N = 1010;
int n, m, p;
int s[N][N], cost[N];
int f[N], g[N][N];
struct Node
{
int v, i, j;
bool operator < (const Node & W) const
{
return v < W.v;
}
};
priority_queue<Node> heap[N];
int get(int x)
{
x %= n;
if (x <= 0)
{
x += n;
}
return x;
}
int main(void)
{
scanf("%d%d%d", &n, &m, &p);
for (int i = 1; i <= n; i++)
{
for (int j = 1; j <= m; j++)
{
scanf("%d", &s[i][j]);
}
}
for (int i = 1; i <= m; i++)
{
for (int j = 1; j <= n; j++)
{
if (j == 1)
{
s[j][i] += s[n][i - 1];
}
else
{
s[j][i] += s[j - 1][i - 1];
}
}
}
memset(f, -0x3f, sizeof f);
memset(g, -0x3f, sizeof g);
f[0] = 0;
for (int i = 1; i <= n; i++)
{
scanf("%d", &cost[i]);
}
for (int i = 1; i <= n; i++)
{
g[0][i] = -cost[get(i + 1)];
heap[get(0 - i)].push({ g[0][i], 0, i });
}
for (int i = 1; i <= m; i++)
{
for (int j = 1; j <= n; j++)
{
auto& h = heap[get(i - j)];
while (h.size())
{
auto t = h.top();
if (i - p > t.i)
{
h.pop();
}
else
{
f[i] = max(f[i], s[j][i] + t.v);
break;
}
}
}
for (int j = 1; j <= n; j++)
{
g[i][j] = f[i] - s[j][i] - cost[get(j + 1)];
heap[get(i - j)].push({ g[i][j], i, j });
}
}
int res = 0;
for (int i = 0; i <= m; i++)
{
res = max(res, f[i]);
}
cout << res << endl;
return 0;
}2025-06-30 来自 浙江
1666,没用万能头
23小时前 来自 江苏
0#include <iostream>
using namespace std;
const int N=1010;
int n,m,p;
int s[N][N],cost[N];
int f[N],g[N][N];
struct Node{
int v,i,j;
bool operator<(const Node & W) const{
return v<W.v;
}
};
priority_queue<Node>heap[N];
int get(int x){
x%=n;
if(x<=0){
x+=n;
}
return x;
}
int main(void){
scanf("%d%d%d",&n,&m,&p);
for (int i=1;i<=n;i++){
for (int j=1;j<=m;j++){
scanf("%d",&s[i][j]);
}
}
for (int i=1;i<=m;i++){
for (int j=1;j<=n;j++){
if(j==1){
s[j][i]+=s[n][i-1];
}
else{
s[j][i]+=s[j-1][i-1];
}
}
}
memset(f,-0x3f,sizeof f);
memset(g,-0x3f,sizeof g);
f[0]=0;
for (int i=1;i<=n;i++){
scanf("%d",&cost[i]);
}
for (int i=1;i<=n;i++){
g[0][i]=-cost[get(i+1)];
heap[get(0-i)].push({g[0][i],0,i});
}
for (int i=1;i<=m;i++){
for (int j=1;j<=n;j++){
auto& h=heap[get(i-j)];
while(h.size()){
auto t=h.top();
if(i-p>t.i){
h.pop();
}
else{
f[i]=max(f[i],s[j][i] t.v);
break;
}
}
}
for (int j = 1; j <= n; j++){
g[i][j]=f[i]-s[j][i]-cost[get(j+1)];
heap[get(i-j)].push({g[i][j],i,j});
}
}
int res=0;
for (int i=0;i<=m;i++){
res = max(res, f[i]);
}
cout<<res<<endl;
return 0;
}2天前 来自 广东
0#include<bits/stdc++.h>是个好东西
2025-08-04 来自 山东
0





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