A13 传纸条 题解
2026-10-03 20:30:35
发布于:江苏
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直接上代码
#include <bits/stdc++.h>
using namespace std;
#define int long long
int a[60][60];
int dp[60][60][60][60];
signed main() {
ios::sync_with_stdio(false);
ios_base::sync_with_stdio(false);
cin.tie(0), cout.tie(0);
int m, n;
cin >> m >> n;
for (int i = 1; i <= m; i++) {
for (int j = 1; j <= n; j++) {
cin >> a[i][j];
}
}
for (int i = 1; i <= m; i++) {
for (int j = 1; j <= n; j++) {
for (int k = 1; k <= m; k++) {
for (int l = 1; l <= n; l++) {
dp[i][j][k][l] = max(dp[i - 1][j][k - 1][l], dp[i - 1][j][k][l - 1]);
dp[i][j][k][l] = max(dp[i][j - 1][k - 1][l], max(dp[i][j][k][l], dp[i][j - 1][k][l - 1]));
dp[i][j][k][l] += a[i][j] + a[k][l];
if (i == k && j == l && !(i == 1 && j == 1 || i == m && j == n)) {
dp[i][j][k][l] = -114514;
}
}
}
}
}
cout << dp[m][n][m][n];
return 0;
}
这里空空如也






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