long long

#include<iostream>
using namespace std;

long long n,cnt = 0,ans = 0;
long long a[10000010];

int main(){
	long long apple = 1; 
	cin >> n;
	while(cnt + apple <= n){
		a[ans] = apple;
		ans++; 
		cnt += apple;
		apple *= 2;
	}
	cout << ans << endl;
	for(int i = 0;i < ans;i++){
		cout << a[i] << endl;
	} 
	return 0;
}

while即可，for找不到循环条件