上午-5

userId_undefined

han11

倔强青铜枚举·枚举小能手

2025-07-18 11:03:59

发布于：河北

8阅读
0回复
0点赞

Palindrome Number Check Function

#include <iostream>
using namespace std;

bool is_pal(int n) {
    // reversed number t, if t == n, then it's a palindrome
    int nn = n, t = 0; // nn is a copy of n
    while (nn > 0) {
        t = t * 10 + nn % 10;
        nn /= 10;
    }
    return t == n; // simplified return statement
}

int main() {
    int n;
    cin >> n;
    cout << (is_pal(n) ? "Yes" : "No") << endl;
    return 0;
}
userId_undefined
去预览
0/2000
暂无数据

这里空空如也

热门讨论