T3
2025-05-08 16:02:50
发布于:浙江
#include <iostream>
#include <algorithm>
#include <vector>
int main() {
int n;
std::cin >> n;
std::vector<int> numbers;
for (int i = 1; i <= n; ++i) {
numbers.push_back(i);
}
do {
for (int i = 0; i < n; ++i) {
std::cout << numbers[i];
if (i < n - 1) {
std::cout << " ";
}
}
std::cout << std::endl;
} while (std::next_permutation(numbers.begin(), numbers.end()));
return 0;
}
全部评论 1
笑点解析:
std::next_permutation
偷鸡2025-05-09 来自 广东
0
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